dirichlet()
function in
the hyper2
packagefunction (powers, alpha)
{
if (!xor(missing(powers), missing(alpha))) {
stop("supply exactly one of powers, alpha")
}
if (missing(powers)) {
powers <- alpha - 1
}
np <- names(powers)
if (is.null(np)) {
stop("supply a named vector")
}
hyper2(as.list(np), d = powers) - hyper2(list(np), d = sum(powers))
}
To cite the hyper2
package in publications, please use
Hankin (2017). We say that non-negative
\(p_1,\ldots, p_n\) satisfying \(\sum p_i=1\) follow a Dirichlet
distribution, and write \(\mathcal{D}(p_1,\ldots,p_n)\), if their
density function is
\[\begin{equation} \frac{\Gamma(\alpha_1+\cdots +\alpha_n)}{\Gamma(\alpha_1)\cdots\Gamma(\alpha_n)} \prod_{i=1}^n p_i^{\alpha_i-1} \end{equation}\]
for some parameters \(\alpha_i>0\). It is interesting in the current context because it is conjugate to the multinomial distribution; specifically, given a Dirichlet prior \(\mathcal{D}(\alpha_1,\ldots,\alpha_n)\) and likelihood function \(\mathcal{L}(p_1,\ldots,p_n)\propto\prod_{i=1}^n p_i^{\alpha_i}\) then the posterior is \(\mathcal{D}(\alpha_1+a_1,\ldots,\alpha_n+a_n)\).
In the context of the hyper2
package, function
dirichlet()
presents some peculiarities, discussed
here.
Consider a three-way trial between players a
,
b
, and c
with eponymous Bradley-Terry
strengths. Suppose that, out of \(4+5+3=12\) trials, a
wins 4,
b
wins 5, and c
wins 3. Then an appropriate
likelihood function would be:
## log(a^4 * (a + b + c)^-12 * b^5 * c^3)
Note the (a+b+c)^-11
term, which is not strictly
necessary according the Dirichlet density function above which has no
such term. However, we see that the returned likelihood function is
\({\propto}
p_{a\vphantom{abc}}^4p_{b\vphantom{abc}}^5p_{c\vphantom{abc}}^3\)
(because \(p_a+p_b+p_c=1\)).
## log(a^4 * (a + b + c)^-12 * b^5 * c^3)
Now suppose we observe three-way trials between b
,
c
, and d
:
## log( b * (b + c + d)^-10 * c * d^8)
The overall likelihood function would be \(L_1+L_2\):
## log(a^4 * (a + b + c)^-12 * b^6 * (b + c + d)^-10 * c^4 * d^8)
## a b c d
## 0.09090991 0.10909114 0.07272658 0.72727237
Observe the dominance of competitor d
, reasonable on the
grounds that d
won 8 of the 10 trials against
b
and c
; and a
, b
,
c
are more or less evenly matched [chi square test, \(p=0.94\)]. Observe further that we can
include four-way observations easily:
## log(a^4 * (a + b + c + d)^-15 * b^3 * c^2 * d^6)
## log(a^8 * (a + b + c)^-12 * (a + b + c + d)^-15 * b^9 * (b + c + d)^-10
## * c^6 * d^14)
Package idiom L1+L2+L3
operates as expected because
dirichlet()
includes the denominator. Sometimes we see
situations in which a competitor does not win any trials. Consider the
following:
## log(a^5 * (a + b + c + d)^-11 * b^3 * d^3)
Above, we see that c
won no trials and is not present in
the numerator of the expression. However, L4
is informative
about competitor c
:
## a b c d
## 4.546526e-01 2.727224e-01 1.020077e-06 2.726240e-01
We see that the maximum likelihood estimate for c
is
zero (to within numerical tolerance). Further, we may reject the
hypothesis that \(p_c=\frac{1}{4}\)
[which might be a reasonable consequence of the assumption that all four
competitors have the same strength]:
##
## Constrained support maximization
##
## data: H
## null hypothesis: sum p_i=1, c = 0.25
## null estimate:
## a b c d
## 0.3122093 0.2162741 0.2500000 0.2215167
## (argmax, constrained optimization)
## Support for null: -14.93581 + K
##
## alternative hypothesis: sum p_i=1
## alternative estimate:
## a b c d
## 4.546526e-01 2.727224e-01 1.020077e-06 2.726240e-01
## (argmax, free optimization)
## Support for alternative: -11.738 + K
##
## degrees of freedom: 1
## support difference = 3.197811
## p-value: 0.01144022 (two sided)
However, observe that we cannot reject the equality hypothesis, that is, \(p_a=p_b=p_c=p_d=\frac{1}{4}\):
##
## Constrained support maximization
##
## data: L4
## null hypothesis: a = b = c = d
## null estimate:
## a b c d
## 0.25 0.25 0.25 0.25
## (argmax, constrained optimization)
## Support for null: -15.24924 + K
##
## alternative hypothesis: sum p_i=1
## alternative estimate:
## a b c d
## 4.546526e-01 2.727224e-01 1.020077e-06 2.726240e-01
## (argmax, free optimization)
## Support for alternative: -11.738 + K
##
## degrees of freedom: 3
## support difference = 3.511242
## p-value: 0.07118459
hyper2
Package: Likelihood Functions for
Generalized Bradley-Terry Models.”
The R Journal 9 (2): 429–39.